## Problem Find the period of the discrete-time signal defined by the equation: $ x(n) = e^{j\pi n} $ > [!Solution]- > > Given that $e^{j\pi}=-1$ the equation can be re-written as: > $ > x(n) = (-1)^{n} > $ > that represents a sequence with alternating $1$ and $-1$ values. The smallest value of $N$ that verifies the equation: > $ > x(n) = x(n+N) > $ > is $N=N_{0}=2$. >